Ionic theory and electrolysis questions | form three Chemistry

(3872) Question Category: Multiple choices

The ionic equation when aqueous ammonium chloride reacts with sodium hydroxide solution is represented as:

  1. 2NH^{+}_{4(aq)} + 2Cl^{-}_{(aq)}
ightarrow 2NH_{3(g)} + Cl_{2(g)} + H_{2(g)}
  2. NH^{+}_{4(aq)} + OH^{-}_{(aq)}
ightarrow NH_{3(g)} + H_{2}O_{(l)}
  3. Na^{+}_{(aq)} + Cl^{-}_{(aq)}
ightarrow NaCl_{(g)}
  4. H^{+}_{(aq)} + OH^{-}_{(aq)}
ightarrow H_{2}O_{(l)}
  5. 2NH^{+}_{4(aq)} + 2Cl^{-}_{(aq)}
ightarrow 2NH_{3(g)} + 2HCl_{(g)}.

Answer / Solution

UNSOLVED

(3875) Question Category: Multiple choices

If a stead current of 2 amperes was passed through an aqueous solution of iron (II) sulphate for 15 minutes, then the mass of iron deposited at the cathode will be:

  1. 54 g
  2. 56 g
  3. 0.54 g
  4. 28 g
  5. 0.52 g.

Answer / Solution

UNSOLVED

(4323) Question Category: Multiple choices

A current of 0.2 A was passed through an electrolyte for 16 minutes and 40 seconds. What is the quantity of electricity produced in coulombs?

  1. 2000 C
  2. 1000 C
  3. 200 C
  4. 0.20 C
  5. 7686 C.

Answer / Solution

Quantity of charge(charge) = Current(ampere) × time(second).

Given  Current=0.2 A, Time 16 minutes and 40 seconds.

Convert 16 minutes to seconds :

1 minute = 60 seconds; hence 16 minutes= 16x60 seconds

Time=960seconds + 40 seconds

Time =1000 seconds.

Lets find the Amount of charge

Amount of charge (Coulombs)= Current (Ampere)x Time(seconds)

Amount of charge=0.2A x1000 s =200 Coulombs

Therefore the answer is C. 200 Coulombs.

  1. 200 C.

 

 

(4337) Question Category: Short answers

Copper obtained from copper pyrites(CuFeS_{2}) is impure for electrical wiring and has to be purified by electrolysis.
(i) Name the electrolyte and the electrodes used during electrolysis.
(ii) Write the observations that can be made during the electrolysis.

Answer / Solution

UNSOLVED

(4911) Question Category: Mathematical Calculation

How long a current of 5A should be passed through a solution of silver chloride in order to deposit 3.24 g of silver metal at the cathode? Given that, the electrochemical equivalent of silver = 1.118 	imes 10^{-3} ge^{-1} .

Answer / Solution

UNSOLVED


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